The pilot of a SpiceJet Q400 plane flying from Delhi to Jabalpur made an emergency call on “May Day” and returned to Delhi after smoke was detected in the cabin.
According to sources, the plane was at an altitude of 5,000 feet when the crew first noticed the smoke and the smoke alarm went off.
“The cabin crew informed the cockpit crew of light smoke in the cabin and a visual inspection found no signs of smoke or damage in the lavatory,” the source said.
The smoke began to thicken as the flight reached an altitude of 14,000 feet. The pilot then informed air traffic control and May Day was declared. Then the flight turned back to Delhi.
Upon safe landing, all passengers were evacuated.
Preliminary investigations indicate an oil leak in the left engine is causing the smoke, sources said.
Sources from the aviation authority, the Directorate-General for Civil Aviation, said it was a technical issue and there was no need to panic.
#CLOCK | A SpiceJet plane operating from Delhi to Jabalpur returned safely to Delhi airport this morning after crew noticed smoke in the cabin while passing 5000 feet; Passengers disembarked safely: spokesman for SpiceJet pic.twitter.com/R1LwAVO4Mk
— ANI (@ANI) July 2, 2022
“A SpiceJet aircraft operating from Delhi to Jabalpur returned safely to Delhi Airport this morning after crew noticed smoke in the cabin while passing 5000ft; passengers disembarked safely,” a SpiceJet spokesman said, according to ANI.
A picture tweeted by the news agency showed a smoky cabin. Visuals also showed passengers disembarking the plane upon its return to Delhi.
This is the second emergency landing for a SpiceJet flight in 15 days. On June 19, a plane bound for Delhi with 185 passengers on board made an emergency landing in Patna just after take-off when its left engine caught fire after a bird strike.